Learn and know **divisibility rule of 7** which is not known by most of us. Do you know the first thing that we will get in the mind, when someone asks what is the **divisibility rule for the number 7**? We definitely say that there is no any divisibility rule for the number 7? Because in our school days they said that there is no divisibility rule of 7. Except **divisibility rule of 7** remaining we will learn i.e. divisibility rule of 4, divisibility rule of 9, and divisibility rule of 6 and so on.

At first I also thought really there is no divisibility rule for 7. But the fact is, there is a divisibility rule for 7. What I know about **divisibility rule of 7**, am sharing with you. So go through it, it will be useful to you. To be frank, there are so many **divisibility rules for 7** exists, but in all these the below given method is simple and easy to do.

*Below given are the steps for divisibility rule of 7:*

*Below given are the steps for divisibility rule of 7:*

Step 1:

In the given number, Double the unit digit and subtract it from remaining number.

Step 2:

Now see the result is divisible by 7 or not. If the result is a big number, again two times (double) of unit digit subtract from remaining number.

One again check the obtained result is divisible by the number 7 or not. Continue this process up to the result is multiple of 7 or 0.

**Some Examples on divisibility rule of 7:**

**Example No.1:**

**Is 5689712 is divisible by the 7 or not?**

Solution:

First double unit digit and subtract from remaining number.

Unit digit is 2, so its double is 4. Other than unit digit, remaining number is 568971.

Now subtract 4 from 568971, we get 568967. Now check 568967 is divisible by 7 or not. If you feel that, it is difficult to find it. No problem, again repeat the process.

Unit digit in 568967 is 7. Double of 7 is 14. Subtract 14 from 56896, we get 56882.

Unit digit in 56882 is 2. Double of 2 is 4. Subtract 4 from 5688, we get 5684.

In 5684, unit digit is 4. Double of 4 is 8. Subtract 8 from 568, we get 560.

In 560, 0 is the unit place. Double of 0 is 0. Subtract 0 from 56, we get 56.

Now it is clear that 56 is divisible by 7. So the above given number **5689712 is divisible by 7**.

**Example No.2:**

**Is the number 6273 is divisible by the 7?**

Solution:

In 6273, unit digit is 3. Double of 3 is 6. So subtract 6 from 627, we get 621.

1 is the unit digit in 621. Double of 1 is 1. Subtract the number 1 from 62, we get the result as 61.

We know that, 61 is not divisible by the number 7, so, the give number **6273 is not divisible by the number 7**.

**Example No.3:**

**Is the number 504 is divisible by the 7?**

Solution:

Unit digit double is 8. Subtract 8 from 50, we get 42. As 42 is divisible by 7, so **504 is divisible by 7**.

**Example No.4:**

**Is the number 1735 is divisible by the 7?**

Solution:

173-(2×5)= 173-10= 163.

16 -(2×3)= 16-6 = 10.

We know that, 10 is not divisible by the number 7. So, the given number **1735 is not divisible by the number 7**.

**Example No.5:**

**Is the number 82149 is divisible by the 7?**

Solution:

8214 – (2×9) = 8214 – 18 = 8196.

819 – (2×6) = 819 – 12 = 807.

80 – (2×7) = 80 – 14 = 66.

We know that, 66 is not divisible by the number 7. So, the given number **82149 is not divisible by the number 7**.

**Example No.6:**

**Is the 99257 is divisible by the 7?**

Solution:

9925 – (2×7) = 9925 – 14 = 9911.

991 – (2×1) = 991 – 2 = 989.

98 –(2×9) = 98 – 18 = 80.

We know that, 80 is not divisible by the number 7. So, the given number **99257 is** **not divisible by the number 7**.

I hope you have understood **divisibility rule of 7** and examples based on it.

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